(6+x-x^2)^1/2=9

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Solution for (6+x-x^2)^1/2=9 equation: 


x in (-oo:+oo)

((x-x^2+6)^1)/2 = 9 // - 9

((x-x^2+6)^1)/2-9 = 0

(x-x^2+6)/2-9 = 0

(x-x^2+6)/2+(-9*2)/2 = 0

x-x^2-9*2+6 = 0

x-x^2-12 = 0

x-x^2-12 = 0

x-x^2-12 = 0

DELTA = 1^2-(-12*(-1)*4)

DELTA = -47

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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